加解密算法实现
(14)

2.jpg

0x00 md5加密

import hashlib

data = '你好'
print(hashlib.md5(data.encode(encoding="UTF-8")).hexdigest())  #32位
print(hashlib.md5(data.encode(encoding="UTF-8")).hexdigest()[8:-8]) 

16位

0x01 RSA加密

指数和模加密无填充1

import rsa

#模
m = "ae068c2039bd2d82a529883f273cf20a48e0b6faa564e740402375a9cb332a029b8492ae342893d9c9d53d94d3ab8ae95de9607c2e03dd46cebe211532810b73cc764995ee61ef435437bcddb3f4a52fca66246dbdf2566dd85fbc4930c548e7033c2bcc825b038e8dd4b3553690e0c438bbd5ade6f5a476b1cbc1612f5d501f"
#指数
e = '10001'
#加密参数
message = '123456'

class Encrypt(object):
    def __init__(self, e, m):
        self.e = e
        self.m = m

    def encrypt(self, message):
        mm = int(self.m, 16)
        ee = int(self.e, 16)
        rsa_pubkey = rsa.PublicKey(mm, ee)
        crypto = self._encrypt(message.encode(), rsa_pubkey)
        return crypto.hex()

    def _pad_for_encryption(self, message, target_length):
        message = message[::-1]
        max_msglength = target_length - 11
        msglength = len(message)

        padding = b''
        padding_length = target_length - msglength - 3

        for i in range(padding_length):
            padding += b'x00'

        return b''.join([b'x00x00', padding, b'x00', message])

    def _encrypt(self, message, pub_key):
        keylength = rsa.common.byte_size(pub_key.n)
        padded = self._pad_for_encryption(message, keylength)

        payload = rsa.transform.bytes2int(padded)
        encrypted = rsa.core.encrypt_int(payload, pub_key.e, pub_key.n)
        block = rsa.transform.int2bytes(encrypted, keylength)

        return block

if __name__ == '__main__':
    en = Encrypt(e, m)
    print(en.encrypt(message))

指数和模加密无填充2

import codecs

def rsa_encrypt(content):
    public_exponent = '010001'
    public_modulus = 'ae068c2039bd2d82a529883f273cf20a48e0b6faa564e740402375a9cb332a029b8492ae342893d9c9d53d94d3ab8ae95de9607c2e03dd46cebe211532810b73cc764995ee61ef435437bcddb3f4a52fca66246dbdf2566dd85fbc4930c548e7033c2bcc825b038e8dd4b3553690e0c438bbd5ade6f5a476b1cbc1612f5d501f'

    content = content[::-1]
    rsa = int(codecs.encode(content.encode('utf-8'), 'hex_codec'),
              16) ** int(public_exponent, 16) % int(public_modulus, 16)
    # 把10进制数rsa转为16进制('x'表示16进制),再取前256位,不够的在最前面补0
    return format(rsa, 'x').zfill(256)

指数和模加密无填充3

import math
if __name__ == '__main__':
    # 实为16进制串,前补0
    e = ''
    # m也需要补00
    m = '008eb933413be3234dddd2730fbb1d05c8848a43d5dc3bdd997f2a9935fba6beb9ffb36854482b0b46cf7e6f9afbbe2e2e7d606fde20bec57dbf722e7985192e8813e6b67628a6f202cf655b7d2ffce4e9dc682dd6034ae706c8e255f25e4051b9ca43f25b3ad686aac9c8f6aeb71d921c13a255c806f78a5a7b9a356c2dd274e3'
    m = int.from_bytes(bytearray.fromhex(m), byteorder='big')
    e = int.from_bytes(bytearray.fromhex(e), byteorder='big')
    # js加密为反向,为保持一致原文应反向处理,所以这里原文实际为204dowls
    plaintext = 'slwod402'.encode('utf-8')
    # 无填充加密逻辑
    input_nr = int.from_bytes(plaintext, byteorder='big')
    crypted_nr = pow(input_nr, e, m)
    keylength = math.ceil(m.bit_length() / 8)
    crypted_data = crypted_nr.to_bytes(keylength, byteorder='big')
    print(crypted_data.hex())

指数和模加密有填充

from cryptography.hazmat.backends import default_backend
from cryptography.hazmat.primitives.asymmetric import rsa
from cryptography.hazmat.primitives.asymmetric import padding
import base64
import binascii

"""
另种rsa加密
"""


def data_encrypt(text):
    """
        RSA 加密
    :param text:    加密前内容
    :return:        加密后内容
    """
    # 判断系统,加载指定模块
    public_exponent = int("010001",16)  #指数
    print(public_exponent)
    public_modulus=int('B23322F080BD5876C0735D585D25C7BC409F637237B07744D27FBF39FB100ABE59DF380EA6BFCDF28C286E7A0CD95BE87F6099F8F39B0E97D9782C3D33FCFB80D43D2F22A9D9417ECFD1A0B8421DEE1CD4B323E8078336E77419A97F94E60A90CA06551202F63819FC8E73425F06ECA4C05BBF8CA32366240A6C36CA61D85019',16)

    # content = 'leadeon' + text + time.strftime("%Y%m%d%H%M%S", time.localtime())
    content = text
    max_length = 117
    # public_key = serialization.load_pem_public_key(key, backend=default_backend())
    public_key = rsa.RSAPublicNumbers(public_exponent, public_modulus).public_key(default_backend())
    data = b''
    for i in range(0, len(content), max_length):
        data += public_key.encrypt(content[i: i + max_length].encode(),
                                   padding.PKCS1v15())
    data = base64.b64encode(data).decode()
    #data =binascii.b2a_hex(data).decode()  hex输出
    return data

公钥加密

import base64
import rsa
from Crypto.PublicKey import RSA

def encryptPassword(data, publicKeyStr):
    '''
    data:内容
    publicKeyStr:不需要-----BEGIN PUBLIC KEY-----开头,-----END PUBLIC KEY-----结尾的格式,只要中间部分即可
    key_encoded:不需要-----BEGIN PUBLIC KEY-----开头,-----END PUBLIC KEY-----结尾的格式
    '''
    key_encoded='''-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCdZGziIrJOlRomzh7M9qzo4ibw
QmwORcVDI0dsfUICLUVRdUN+MJ8ELd55NKsfYy4dZodWX7AmdN02zm1Gk5V5i2Vw
GVWE205u7DhtRe85W1oR9WTsMact5wuqU6okJd2GKrEGotgd9iuAJm90N6TDeDZ4
KHEvVEE1yTyvrxQgkwIDAQAB
-----END PUBLIC KEY-----'''
    # 1、base64解码
    publicKeyBytes = base64.b64decode(publicKeyStr.encode())
    # 3、生成publicKey对象
    key = RSA.import_key(publicKeyBytes)
    #key = RSA.import_key(key_encoded)
    # 4、对原密码加密
    encryptPassword = rsa.encrypt(data.encode(), key)
    return base64.b64encode(encryptPassword).decode()

0x02 DES

DES加密与解密以及hex输出和bs64格式输出

import pyDes
import base64

Key = "12345678"  #加密的key

Iv = None   #偏移量


def bytesToHexString(bs):
    '''
    bytes转16进制
    '''
    return ''.join(['%02X ' % b for b in bs])
def hexStringTobytes(str):
    '''16进制转bytes'''
    str = str.replace(" ", "")
    return bytes.fromhex(str)

# 加密
def encrypt_str(data):
    # 加密方法
    #padmode填充方式
    #pyDes.ECB模式
    method = pyDes.des(Key, pyDes.ECB, Iv, pad=None, padmode=pyDes.PAD_PKCS5)
    # 执行加密码 hex输出
    k = method.encrypt(data)
    data = bytesToHexString(k).replace(' ','')
    #bs64手粗
    #data =base64.b64encode(k)
    return data

# 解密
def decrypt_str(data):
    method = pyDes.des(Key, pyDes.ECB, Iv, pad=None, padmode=pyDes.PAD_PKCS5)
    k =hexStringTobytes(data)
    #bs64
    #k = base64.b64decode(data)
    return method.decrypt(k)


Encrypt = encrypt_str("aaa")
print(Encrypt)
Decrypt = decrypt_str(Encrypt)
print(Decrypt)

0x03 3DES

import hashlib, base64
import json
from cryptography.hazmat.primitives.padding import PKCS7
from cryptography.hazmat.primitives.ciphers import algorithms
from Crypto.Cipher import DES3

def pkcs7padding(text):
    """
    明文使用PKCS7填充
    最终调用DES3加密方法时,传入的是一个byte数组,要求是16的整数倍,因此需要对明文进行处理
    :param text: 待加密内容(明文)
    :return:
    """
    bs = DES3.block_size  # 16
    length = len(text)
    bytes_length = len(bytes(text, encoding='utf-8'))
    # tips:utf-8编码时,英文占1个byte,而中文占3个byte
    padding_size = length if (bytes_length == length) else bytes_length
    padding = bs - padding_size % bs
    # tips:chr(padding)看与其它语言的约定,有的会使用''
    padding_text = chr(padding) * padding
    return text + padding_text


def pkcs7_unpad(content):
    """
    解密时候用
    :param content:
    :return:
    """
    if not isinstance(content, bytes):
        content = content.encode()
    pad = PKCS7(algorithms.DES3.block_size).unpadder()
    pad_content = pad.update(content) + pad.finalize()
    return pad_content


def encrypt(key, content):
    """
    DES3加密
    key,iv使用同一个
    模式cbc
    填充pkcs7
    :param key: 密钥
    :param content: 加密内容
    :return:
    """
    key_bytes = bytes(key, encoding='utf-8')
    iv = key_bytes
    cipher = DES3.new(key_bytes, DES3.MODE_ECB)
    # 处理明文
    content_padding = pkcs7padding(content)
    # 加密
    encrypt_bytes = cipher.encrypt(bytes(content_padding, encoding='utf-8'))
    # 重新编码
    result = str(base64.b64encode(encrypt_bytes), encoding='utf-8')
    return result

def decrypt(key,text):
    key_bytes = bytes(key, encoding='utf-8')
    iv = key_bytes
    cryptos = DES3.new(key_bytes, DES3.MODE_ECB)
    data = cryptos.decrypt(text)
    return json.loads(pkcs7_unpad(data))

0x04 AES加密

AES_ECB_pkcs5padding(不兼容中文)

from Crypto.Cipher import AES
import base64

class Aes_ECB(object):
    def __init__(self):
        self.key = 'XXXXXXXXXXX'  #秘钥
        self.MODE = AES.MODE_ECB
        self.BS = AES.block_size
        self.pad = lambda s: s + (self.BS - len(s) % self.BS) * chr(self.BS - len(s) % self.BS)
        self.unpad = lambda s: s[0:-ord(s[-1])]

    # str不是16的倍数那就补足为16的倍数
    def add_to_16(value):
        while len(value) % 16 != 0:
            value += ''
        return str.encode(value)  # 返回bytes

    def AES_encrypt(self, text):
        aes = AES.new(Aes_ECB.add_to_16(self.key), self.MODE)  # 初始化加密器
        encrypted_text = str(base64.encodebytes(aes.encrypt(Aes_ECB.add_to_16(self.pad(text)))),
                             encoding='utf-8').replace('n', '')  # 这个replace大家可以先不用,然后在调试出来的结果中看是否有'n'换行符
        # 执行加密并转码返回bytes
        return encrypted_text

AES_ECB_pkcs7padding(支持中文)

import hashlib, base64
from Crypto.Cipher import AES
from cryptography.hazmat.primitives.padding import PKCS7
from cryptography.hazmat.primitives.ciphers import algorithms


def pkcs7padding(text):
    """
    明文使用PKCS7填充
    最终调用AES加密方法时,传入的是一个byte数组,要求是16的整数倍,因此需要对明文进行处理
    :param text: 待加密内容(明文)
    :return:
    """
    bs = AES.block_size  # 16
    length = len(text)
    bytes_length = len(bytes(text, encoding='utf-8'))
    # tips:utf-8编码时,英文占1个byte,而中文占3个byte
    padding_size = length if (bytes_length == length) else bytes_length
    padding = bs - padding_size % bs
    # tips:chr(padding)看与其它语言的约定,有的会使用''
    padding_text = chr(padding) * padding
    return text + padding_text


def pkcs7_unpad(content):
    """
    解密时候用
    :param content:
    :return:
    """
    if not isinstance(content, bytes):
        content = content.encode()
    pad = PKCS7(algorithms.AES.block_size).unpadder()
    pad_content = pad.update(content) + pad.finalize()
    return pad_content


def encrypt(key, content):
    """
    AES加密
    key,iv使用同一个
    模式cbc
    填充pkcs7
    :param key: 密钥
    :param content: 加密内容
    :return:
    """
    key_bytes = bytes(key, encoding='utf-8')
    iv = key_bytes
    cipher = AES.new(key_bytes, AES.MODE_ECB)
    # 处理明文
    content_padding = pkcs7padding(content)
    # 加密
    encrypt_bytes = cipher.encrypt(bytes(content_padding, encoding='utf-8'))
    # 重新编码
    result = str(base64.b64encode(encrypt_bytes), encoding='utf-8')
    return result

def decrypt(key,text):
    key_bytes = bytes(key, encoding='utf-8')
    iv = key_bytes
    cryptos = AES.new(key_bytes, AES.MODE_ECB)
    data = cryptos.decrypt(text)
    return json.loads(pkcs7_unpad(data))

AES_128192256怎么识别

根据key的长度进行识别
128 16位
192 24位
256 32位
#基本上不足的部分都是以0进行填充

ECB和CBC在代码实现上的区别

CBC相比ECB多一个偏移量,至于其他地方代码区别不大

0x05 SM2/SM4

GmSSL是一个开源的加密包的python实现,支持SM2/SM3/SM4等国密(国家商用密码)算法、项目采用对商业应用友好的类BSD开源许可证,开源且可以用于闭源的商业应用。

安装

pip install gmssl
#https://github.com/duanhongyi/gmssl/blob/master/README.md官方文档

初始化CryptSM2

import base64
import binascii
from gmssl import sm2, func
#16进制的公钥和私钥
private_key = '00B9AB0B828FF68872F21A837FC303668428DEA11DCD1B24429D0C99E24EED83D5'
public_key = 'B9C9A6E04E9C91F7BA880429273747D7EF5DDEB0BB2FF6317EB00BEF331A83081A6994B8993F3F5D6EADDDB81872266C87C018FB4162F5AF347B483E24620207'
sm2_crypt = sm2.CryptSM2(
    public_key=public_key, private_key=private_key)

encrypt和decrypt

#数据和加密后数据为bytes类型
data = b"111"
enc_data = sm2_crypt.encrypt(data)
dec_data =sm2_crypt.decrypt(enc_data)
assert dec_data == data

sign和verify

data = b"111" # bytes类型 random_hex_str =
func.random_hex(sm2_crypt.para_len) sign = sm2_crypt.sign(data,
random_hex_str) # 16进制 assert sm2_crypt.verify(sign, data) # 16进制

初始化CryptSM4

from gmssl.sm4 import CryptSM4, SM4_ENCRYPT, SM4_DECRYPT

key = b'3l5butlj26hvv313'
value = b'111' #  bytes类型
iv = b'x00x00x00x00x00x00x00x00x00x00x00x00x00x00x00x00' #  bytes类型
crypt_sm4 = CryptSM4()

encrypt_ecb和decrypt_ecb

crypt_sm4.set_key(key, SM4_ENCRYPT)
encrypt_value = crypt_sm4.crypt_ecb(value) #  bytes类型
crypt_sm4.set_key(key, SM4_DECRYPT)
decrypt_value = crypt_sm4.crypt_ecb(encrypt_value) #  bytes类型
assert value == decrypt_value

encrypt_cbc和decrypt_cbc

crypt_sm4.set_key(key, SM4_ENCRYPT)
encrypt_value = crypt_sm4.crypt_cbc(iv , value) #  bytes类型
crypt_sm4.set_key(key, SM4_DECRYPT)
decrypt_value = crypt_sm4.crypt_cbc(iv , encrypt_value) #  bytes类型
assert value == decrypt_value

0x06 其他的加密

base64加密

import base64 #base64也是用来加密的,但是这个是可以解密的

s = "password"
print(base64.b64encode(s.encode()) )  #加密

uuid

#有时候你会看到一些比如xxxx-xxxx-xxx-xxx误以为是加密其实很多是uuid模块自动生成的
随机数格式为:xxxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxx

python的uuid模块提供UUID类和函数uuid1(), uuid3(), uuid4(), uuid5()

1.uuid.uuid1([node[, clock_seq]])
基于时间戳

使用主机ID, 序列号, 和当前时间来生成UUID, 可保证全球范围的唯一性. 但由于使用该方法生成的UUID中包含有主机的网络地址, 因此可能危及隐私. 该函数有两个参数, 如果 node 参数未指定, 系统将会自动调用 getnode() 函数来获取主机的硬件地址. 如果 clock_seq 参数未指定系统会使用一个随机产生的14位序列号来代替.

2.uuid.uuid3(namespace, name)
基于名字的MD5散列值

通过计算命名空间和名字的MD5散列值来生成UUID, 可以保证同一命名空间中不同名字的唯一性和不同命名空间的唯一性, 但同一命名空间的同一名字生成的UUID相同.

3.uuid.uuid4()
基于随机数

通过随机数来生成UUID. 使用的是伪随机数有一定的重复概率.

4.uuid.uuid5(namespace, name)
基于名字的SHA-1散列值

md5

import hashlib

#注意加密顺序 
m=hashlib.md5('加密内容'.encode('utf8'))
m.update(b"盐")
sign = m.hexdigest()

字符串和16进制字符串之间转换

import binascii

binascii.b2a_hex('字符串'.encode())  输出b'e5ad97e7aca6e4b8b2'
binascii.a2b_hex('e5ad97e7aca6e4b8b2').decode()   输出 '字符串'

HmacSHA256加密算法

from hashlib import sha256
import hmac

def get_sign(data, key):
    key = key.encode('utf-8')
    message = data.encode('utf-8')
    sign = base64.b64encode(hmac.new(key, message, digestmod=sha256).digest())
    sign = str(sign, 'utf-8')
    print(sign)
    return sign

0x07 RSA逆向计算

# coding = utf-8
import sys
def computeD(fn, e):
    (x, y, r) = extendedGCD(fn, e)
    #y maybe < 0, so convert it
    if y < 0:
        return fn + y
    return y
 
def extendedGCD(a, b):
    #a*xi + b*yi = ri
    if b == 0:
        return (1, 0, a)
    #a*x1 + b*y1 = a
    x1 = 1
    y1 = 0
    #a*x2 + b*y2 = b
    x2 = 0
    y2 = 1
    while b != 0:
        q = a / b
        #ri = r(i-2) % r(i-1)
        r = a % b
        a = b
        b = r
        #xi = x(i-2) - q*x(i-1)
        x = x1 - q*x2
        x1 = x2
        x2 = x
        #yi = y(i-2) - q*y(i-1)
        y = y1 - q*y2
        y1 = y2
        y2 = y
    return(x1, y1, a)
 
p = 3487583947589437589237958723892346254777
q = 8767867843568934765983476584376578389
e = 65537
 
n = p * q
fn = (p - 1) * (q - 1)
 
d = computeD(fn, e)

# file = open(r'D_data.txt',mode='w')
#    file.write("hello")
#    file.close()
print (int(d))

第二种

e = 65537
p = 9648423029010515676590551740010426534945737639235739800643989352039852507298491399561035009163427050370107570733633350911691280297777160200625281665378483
q = 11874843837980297032092405848653656852760910154543380907650040190704283358909208578251063047732443992230647903887510065547947313543299303261986053486569407
n = p*q
#密文
C = 83208298995174604174773590298203639360540024871256126892889661345742403314929861939100492666605647316646576486526217457006376842280869728581726746401583705899941768214138742259689334840735633553053887641847651173776251820293087212885670180367406807406765923638973161375817392737747832762751690104423869019034

d = 56632047571190660567520341028861194862411428416862507034762587229995138605649836960220619903456392752115943299335385163216233744624623848874235303309636393446736347238627793022725260986466957974753004129210680401432377444984195145009801967391196615524488853620232925992387563270746297909112117451398527453977

#求明文
M = pow(C,d,n)    #快速求幂取模运算
print(M)

第三种

p =
8637633767257008567099653486541091171320491509433615447539162437911244175885667806398411790524083553445158113502227745206205327690939504032994699902053229

q = 12640674973996472769176047937170883420927050821480010581593137135372473880595613737337630629752577346147039284030082593490776630572584959954205336880228469

dp = 6500795702216834621109042351193261530650043841056252930930949663358625016881832840728066026150264693076109354874099841380454881716097778307268116910582929

dq = 783472263673553449019532580386470672380574033551303889137911760438881683674556098098256795673512201963002175438762767516968043599582527539160811120550041

c = 24722305403887382073567316467649080662631552905960229399079107995602154418176056335800638887527614164073530437657085079676157350205351945222989351316076486573599576041978339872265925062764318536089007310270278526159678937431903862892400747915525118983959970607934142974736675784325993445942031372107342103852

import gmpy2
I = gmpy2.invert(q,p)
mp = pow(c,dp,p)
mq = pow(c,dq,q)               #求幂取模运算

m = (((mp-mq)*I)%p)*q+mq       #求明文公式

print(hex(m))          #转为十六进制
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